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26s^2-31s=0
a = 26; b = -31; c = 0;
Δ = b2-4ac
Δ = -312-4·26·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-31}{2*26}=\frac{0}{52} =0 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+31}{2*26}=\frac{62}{52} =1+5/26 $
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